If the factors of a² + b² + 2(ab + bc + ca) are (a + b + m) and (a + b + nc), then the value of (m + n) is:
(A) 0
(B) 2
(C) 4
(D) 6
Answers
Answered by
47
a^2 + b^2 + 2(ab+bc+ca) = a^2 + b^2 + c^2 +2ab + 2bc +2ac -c^2 = (a+b+c)^2 - c^2 = (a+b+2c)(a+b) this means m=0 and n=2 so m+n= 0+2 = 2
Answered by
17
after factorization the factors are (a+b)(a+b+2c)
so m=0, n=2
m+n=2
so m=0, n=2
m+n=2
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Regan2001:
Madam.. Plz check the sum again... Ur values for m and n are 0 and 1 respectively.. So if u add m and n u r getting 0+1 = 1... But check the options in the question.. They don't match with the value 1.. So I think the way u did the sum may be incorrect.. I hope u will understand what I am trying to say
yeah I missed 2 while factorization tnx for ur correction
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