If the fifth term is 18, common difference is 4, find the first term and tenth term of the sequence.
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Let a be the first term ,d be the common difference,n be the number of terms,
n=5,d=4,5th term=18
nth term=a+(n-1)d
5th term=a+(5–1)*4
18=a+16
a=18–16=2
First term is 2
To find the 10 term
n=10,a=2,d=4
nth term=a+(n--1)d
10 th term=2+(10–1)*4=2+9*4=2+36=38
Answer first term=2
Tenth term=38
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