If the fifth term of ap is 5.then the sum of first 9 terms is
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it has given that the fifth term of an ap is 5.
To find : The sum of first 9 terms is ......
solution : we know nth term of an ap is given by, Tn = a + (n - 1)d
so, 5th term , T₅ = a + (5 - 1)d = a + 4d = 5 .....(1)
now sum of n terms of an ap is given by,
Sn = n/2 [2a + (n - 1)d ]
so, sum of first 9 terms = 9/2 [2a + (9 - 1)d]
= 9/2 [2a + 8d ]
= 9 (a + 4d)
from equation (1) we get,
= 9 × 5
= 45
Therefore the sum of 9 term of the ap is 45.
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