if the figure AD is line drawn from the vertex A of triangle ABC TO its opposite side if BD:DC=3:4then BD, DC, area of triangle ABD, area of triangle ADC, area of triangleABD
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If a perpendicular line is drawn from vertex A to the opposite side BC in triangle ABC, we get AD square = BD * DC. How can it be proven that ABC is a right angled triangle? Extend AD to meet the circumcircle of the triangle at E. Then AD*DE = BD*... ... bisects angle ABC. If AD=9 and DC=7,
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