Question

if the final velocity of two body falling freely is 4:3,find the ratio of height from which they fall

Answer 1

INITIAL VELOCITY = 0

V² = U²+2GH

A = 10 M/S²

(4X)² = 20H

4X = √20H

H = 4X/√20
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(3X)² = U²+2AH

(3X)² = 2AH

3X = √20H

H = 3X/√20
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$\frac{h}{h} = \frac{ \frac{4x}{ \sqrt{20} } }{ \frac{3x}{ \sqrt{20} } } \\ = \frac{4x}{ \sqrt{20} } \times \frac{ \sqrt{20} }{3x} \\ = \frac{4x}{3x} \\ = \frac{4}{3}$

RATIOS OF THEIR HEIGHTS WILL BE 4:3

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