CBSE BOARD XII, asked by NancyAjram637, 3 days ago

If the first and 8th term of G.P.is x^-4 andx^52 and the second term is x^t ; then t

Answers

Answered by gyaneshwarsingh882
0

Answer:

a1= 1/x^4

a2=x^m

r=a2/a1

ATQ

a8=ar^7

x^52=1/x^4(1/x^4 *x^(m+4)^7)

x^52=(x^-4(x^(7m+28)))

x^52=(x^7m+28-4)

X^52=x^7m+24

52=7m+24

52-24=7m

28=7m

28/7=m

4=m

Explanation:

a1= 1/x^4a2=x^mr=a2/a1ATQa8=ar^7x^52=1/x^4(1/x^4 *x^(m+4)^7)x^52=(x^-4(x^(7m+28)))x^52=(x^7m+28-4)X^52=x^7m+2452=7m+2452-24=7m28=7m28/7=m4=m

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