if the first and last term of an apre 10 and (-10) how many terms there d=(-1)
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putting the values in formula and solving further.
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Answer:
a1 = 10, an = -10, d = -1
an = a + (n -1) d
-10 = 10 + (n-1) × -1
-10 = 10 -1n + 1
-10 = 10 + 1 -1n
-10 = 11 - 1n
-11 -10 = - 1n
-21 = -1n
21 = n
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