Question

If the first even number is 'd' , then next 3 consecutive even numbers are ____________

Answer 1

Answer:

d+1,d+2,d+3

Step-by-step explanation:

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Answer 2

Answer:

Let 2n = the smallest consecutive even number.

Let 2(n + 1) = 2n + 2 = the next consecutive even number, and ...

Let 2(n + 2) = 2n + 4 = the third consecutive even number.

Since the sum of these 3 consecutive even numbers is 60, we can write the following equation:

2n + (2n + 2) + (2n + 4) = 60

2n + 2n + 2 + 2n + 4 = 60

By the Commutative Property of Addition, i.e., a + b = b + a, we have on the left side of the equation:

2n + 2n + 2n + 2 + 4 = 60

Now, collecting like-terms on the left side, we get:

(2 + 2 + 2)n + 6 = 60

(6)n + 6 = 60

6n + 6 = 60

Now, in order to solve for n, we begin isolating n on the left side of the equation by subtracting 6 from both sides:

6n + 6 - 6 = 60 - 6

6n + 0 = 54

6n = 54

Now, finish solving for n by dividing both sides by 6:

(6n)/6 = 54/6

(6/6)n = 54/6

(1)n = 9

n = 9

Therefore, the smallest consecutive even number is:

2n = 2(9)

2n = 18

CHECK:

2n + (2n + 2) + (2n + 4) = 60

2n + 2n + 2 + 2n + 4 = 60

2(9) + 2(9) + 2 + 2(9) + 4 = 60

18 + 18 + 2 + 18 + 4 = 60

36 + 2 + 18 + 4 = 60

56 + 4 = 60

60 = 60

Therefore, the smallest consecutive even number is indeed 18.

Step-by-step explanation:

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