Question

If the first number is 20%less than the second number and the second number is 25% more than 100,find the first number.

Answer 1

Answer:

100

Step-by-step explanation:

Let the first number be 'a' and the second number be 'b'.

Given that b is 25% more than 100.

25% = 25/100

∴ b  = 100 + 25% more than 100

      = 100 + (25 / 100 x 100)  (25% of a number 'c' equals 25 / 100 x c)

=> b = 100 + 25

       = 125

Also it is given that the a is 20%less than the b, i.e., 20%less than 125.

∴ a = b - 20/100xb

     = 125 - 1/5x125

     = 125 - 25

     = 100

i.e., the first number is 100.