If the first number is 80% of another . and their difference is 2. find both numbers? , it is given that the sum of these two number is divisible by 2 and 3.
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Let second number is=X
Then first number is=80% of X
A/Q
x-4x/5=2 (lcm=5)
5x-4x/5=2
x=5×2
x=10
Second Number=10
First Number=4x/5
=4×10/5
=8
First Number=8
Second Number=10
Sum=8+10
=18
Yes it is divisble by 2 and 3
hOpe you understand
Thanks
Mark brainleist
Then first number is=80% of X
A/Q
x-4x/5=2 (lcm=5)
5x-4x/5=2
x=5×2
x=10
Second Number=10
First Number=4x/5
=4×10/5
=8
First Number=8
Second Number=10
Sum=8+10
=18
Yes it is divisble by 2 and 3
hOpe you understand
Thanks
Mark brainleist
sibi75:
hi maan
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