Math, asked by maaan75, 1 year ago

If the first number is 80% of another . and their difference is 2. find both numbers? , it is given that the sum of these two number is divisible by 2 and 3.

Answers

Answered by pratyush4211
2
Let second number is=X
Then first number is=80% of X
 = 8 0\% \times x \\ \\ \frac{80}{100} \times x = \frac{4x}{5} \\ second \: number = \frac{4x}{5}
A/Q
x-4x/5=2 (lcm=5)
5x-4x/5=2
x=5×2
x=10

Second Number=10
First Number=4x/5
=4×10/5
=8

First Number=8
Second Number=10


Sum=8+10
=18

Yes it is divisble by 2 and 3

hOpe you understand
Thanks
Mark brainleist


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