Question

if the first quartile is 142 and the semi-inter quartile range is 18, then Upper quartile
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Answer 1

Answer:

The median is 160. The semi interquartile range is I=18

Answer 2

Given,

The first quartile =142.

The semi-inter quartile range = 18.

To Find,

The value of the upper quartile.

Solution,

We are given the value of the first quartile, $Q_{1}$ = 142.

The value of semi interquartile range, I =18.

Let's assume the upper quartile ,$Q_{2}$=x.

We Know that semi interquartile range, I=$\frac{Q_{2}-Q_{1} }{2}$.

Hence we can say $\frac{x-142}{2} =18$.

⇒x-142=36.

⇒x=36+142=178.

Hence, the upper quartile is 178.