If the first quartile is 142 and the semi-interquartile range is 18, find the median
(assuming the distribution to be symmetrical).
Answers
Answer:
I don't know
Explanation:
sorry I didn't get the answer
Median = 160
Explanation:
Given that,
First quartile, Q1 = 142
Semi-interquartile range = 18
Assuming the distribution to be symmetrical,
Semi-interquartile range = (Q3 - Q1) ÷ 2
18 = (Q3 - 142) ÷ 2
36 = Q3 - 142
Q3 = 36 - 142
Q3 = 178
Median = (Q3 + Q1) ÷ 2
= (178 + 142) ÷ 2
= 320 ÷ 2
= 160
Therefore, the median of this distribution is 160.
Learn More:
If the first quartile and mean deviation
brainly.in/question/12981454
If the third quartile is 30 and median is 22 find the coefficient of quartile deviation
brainly.in/question/12875627