Question

If the first quartile is 142 and the semi-interquartile range is 18, find the median(assuming the distribution to be symmetrical).​

Answer 1

the median = 160 where  Q₁ = 142 &  semi-interquartile range is 18

Step-by-step explanation:

The formula for semi-interquartile range =  ( Q₃ - Q₁)/2

Q₁ = 142

semi-interquartile range  = 18

=> ( Q₃ - 142)/2  = 18

=> Q₃ - 142 = 36

=> Q₃ = 178

Median = ( Q₃ + Q₁)/2

= ( 142 + 178)/2

= 160

the median = 160

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If the third quartile is 30 and median is 22 find the coefficient of quartile deviation

https://brainly.in/question/12875627

Answer 2

Answer:

The median is 160.

Step-by-step explanation:

We have given,

The first quartile $Q_1=142$

The semi interquartile range is I=18.

Using the formula of semi interquartile range is given by,

$I=\frac{Q_3-Q_1}{2}$

Substitute the values,

$18=\frac{Q_3-142}{2}$

$36=Q_3-142$

$Q_3=36+142$

$Q_3=178$

The third qaurtile is $Q_3=178$

The median formula is given by,

$M=\frac{Q_3+Q_1}{2}$

$M=\frac{142 + 178}{2}$

$M=\frac{320}{2}$

$M=160$

Therefore, the median is 160.

#Learn More

Meadian and Quartile

brainly.in/question/12875627, Answered by Amitnrw