If the first second and last term of arithmetic series are a, b, &c then nth term is
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since a, b and C are in A.P ,
here 1st term=a,
common difference=(b-a),
then
9th term=[2×a+(9-1)×(b-a)],
=[2a+8×(b-a)],
=[2a+8b-8a],
=(8b-6a)
here 1st term=a,
common difference=(b-a),
then
9th term=[2×a+(9-1)×(b-a)],
=[2a+8×(b-a)],
=[2a+8b-8a],
=(8b-6a)
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