Question

If the first team and common difference of an A.P are 6 and 5 respectively, find its 3rd term.​

Answer 1

Answer :

Given,

first term (a) = 6

and common difference (d) = 5

Then, the 3rd term of the AP is

= a + (3 - 1)d

= a + 2d

= 6 + 2 (5)

= 6 + 10

= 16

Rules :

If we consider the following AP sequence

a, a + d, a + 3d, a + 4d, ...

whose first term is a and the common difference is d, then we can compute the nth term as a + nd.

Answer 2

Answer:

First term,a=6

Common difference d=5

an=a+(n-1)d

a3=6+(3-1)5

a3=6+2(5)

a3=6+10

a3=16

Third term of an AP is 16