If the first term (a) and the common difference (d) of a certain (A.P) is 4 and 0 respectively. Find the first four terms of that A.P
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Given the first term is 4 an common difference = 0
Therefore 2nd term = a+d = 4+0 =4
Similarly 3rd term = a+2d = 4+0 =4
4th term = a+3d = 4+0 =4
The first 4 terms are 4,4,4,4
Therefore 2nd term = a+d = 4+0 =4
Similarly 3rd term = a+2d = 4+0 =4
4th term = a+3d = 4+0 =4
The first 4 terms are 4,4,4,4
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The first four term is 4,4,4,4
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