If the first term (a) and the common difference (d) of a certain Arthimetic progression (A. P) is 4 and 0 respectively. find the first four terms of AP
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a = 4
d = 0
T1 = a = 4
T2 = a+d = 4 +0 = 4
T3 = a+2d = 4 + 2*0 = 4
T4 = a+3d = 4 + 3*0 = 4
First four terms are 4,4,4 and 4
d = 0
T1 = a = 4
T2 = a+d = 4 +0 = 4
T3 = a+2d = 4 + 2*0 = 4
T4 = a+3d = 4 + 3*0 = 4
First four terms are 4,4,4 and 4
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a = 4
d = 0
Since d is 0
Hence, AP will be 4, 4, 4, 4
d = 0
Since d is 0
Hence, AP will be 4, 4, 4, 4
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