if the first term and common difference of an A.P are 5and6 find the 3rd term
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Answer:
Let series
A1,A2,A3........An be in AP
Then we can say,
A2 = A1+ d {where d is common difference; d = (a2-a1)}
Similarly,
nth term = First term + d *(n-1)
{where n is total number of terms}
Here,
A5 = 5 and A6 = 6
Therefore, d=(6-5)=1
Since we know,
A5 = A1 + d*(n-1)
=> 5 = A1 + 1*(5-1)
=> 5= A1 + 4
=> A1=1 -------(1)
Similarly,
A11 = A1 + d*(11-1)
=> A11 = 1 + 1*(10) { from eq(1)}
A11 = 11
Alternative:-
Since, the Common Diff is 1
and 5th & 6th term are 5 and 6 respectively.
Hence the 11th term will be 11.
Thank You
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