if the first term and the common difference is 6 and 5 fond its third term
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Step-by-step explanation:
first term = 6
common difference = 5
3rd term = a + 2d = 6 + 2(5) = 6 + 10 = 16
the 3rd term is 16
the series is
6, 11, 16,.......
Answered by
0
Step-by-step explanation:
hey mate i understood this like :
1st term =6
difference =5
n =3
an = a +( n-1 )×d
an = 6 +( 3-1 )×5
an = 6 +( 15-5 )
an = 6 + 10
an = 16 ( 1 method )
another method also have
a , ( a + 1d ) , ( a + 2d )
6 , (6+1×5 ) , ( 6 + 2×5 )
6 , ( 6+5 ) , ( 6 + 10 )
6 , 11 , 16
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