Question

If the first term and the common difference of an arithmetic progression are 6 and 5 find the third term?

Answer 1

Answer:

Step-by-step explanation:

First term, a = 6

Common difference d = 5

an = a + ( n - 1 ) d

a³ = 6 + ( 3 - 1 ) 5

a³ = 6 + 2 ( 5 )

a³ = 6 + 10

a³ = 16

Third term of an AP is 16

Answer 2

Answer:

16 is the third term of the AP

Step-by-step explanation:

Given:

a (first term) = 6

d (difference between successive terms) = 5

n (nth term) = 3

To find;

$A_3$ ( 3rd term of the AP)

Using the formula ;

$A_n = a+(n-1)d\\\\A_3=6+(3-1)5\\\\A_3 = 6+(2)5\\\\A_3=6+10\\\\A_3=16$

Therefore the third term of the AP is 16.

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