Question

. If the first term and the last term of an AP are 1 and II and sum of its term is 36, then find the number of terms in AP.

Answer 1

Answer:

the first term = 1

the last term = 11

sum of its term = 36 = n/2(first term + last term)

n/2(1 + 11)=36

12n/2 = 36

n=72/12

n=6

Hence,

the number of terms in AP =n=6