If the first term changes to 10 and the common difference remains the same then write the new A.P.
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first term = a
common difference = d
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Answer:
The new series is 10, 10+d, 10+3d ... 10(n-1)d
Step-by-step explanation:
Given problem
If the first term changes to 10 and the common difference remains the same then write the new A.P
We know that in AP (Arithmetic Progression) 'a' is the first term and d is the common difference
Then series is a, a+d, a+2d, a+3d... a+(n-1)d
if a is changes to 10 and common difference is same as d then
⇒ first term, a = 10
⇒ 2nd term, a + d = 10+d
⇒ 3rd term, a + 2d = 10 + 3d
⇒ nth term, a + (n-1)d = 10 +(n-1)d
the new series is 10, 10+d, 10+3d ... 10(n-1)d
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