If the first term of an A.P is 8 and 12th term is 63, then sum of 12 terms of an A.P is
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Answered by
0
Answer:
426
Step-by-step explanation:
a=8
a12=63
Sn=n/2(a+an)
S12=12/2(8+a12)
S12=6(8+63)
=6(71)
=426
Answered by
0
Answer:
First term=a=8.
a12=63.
s12=?.
sn=n/2(a+an).
s12=12/2(a+a12).
s12=6(8+63).
s12=6(71).
s12=426.
I think this is your answer.
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