Question

if the first term of an ap is-1 and common difference is -3 then 12 term is​

Answer 1

Step-by-step explanation:

T12 = a + 11d

= -1 + 11 ×(-3)

= - 1 - 33

= -34

Answer 2

Answer:

-34

Step-by-step explanation:

1st term of ap = a1 = -1

common difference = d = -3

[ 1st term of ap = a1 = a

2nd term of ap = a2 = a + d

3rd term of ap = a3 = a + 2×d

4th term of ap = a4 = a + 3×d

5th term of ap = a5 = a + 4×d

6th term of ap = a6 = a + 5×d

7th term of ap = a7 = a + 6×d

8th term of ap = a8 = a + 7×d

9th term of ap = a9 = a + 8×d

10th term of ap = a10 = a + 9×d

11th term of ap = a11 = a + 10×d

12th term of ap = a12 = a + 11×d ]* just for explanation*

Hence,

12th term = a12 = a + 11×d

= -1 + ( 11× -3)

= -1 + ( -33)

= -1 -33

= -34

MARK AS BRAINLIEST