Question

if the first term of an ap is 2 and common difference is 4 then sum of its first 40 terms is​

Answer 1

✪  $\huge{\red{\underline{\overline{\mathbf{Question}}}}}$  ✪

→if the first term of an ap is 2 and common difference is 4 then sum of its first 40 terms is

✪  $\huge{\green{\underline{\overline{\mathbf{Answer}}}}}$  ✪

⇒Given:

• a = 2
• d = 4
• n = 40

⇒To Find:

• $S_{40}=?$

⇒Solution:

⇒$S_{40}=\frac{40}{2}(2\times 2+(40-1)\times 4)$

⇒$S_{40}=20(4+39\times 4)$

⇒$S_{40}=20\times 160$

⇒$\huge{\pink{\underbrace{\overbrace{S_{\tiny{40}}=3200}}}}$

______________________________________

Formulas Used :-

• $S_n=\frac{n}{2}(2a+(n-1)d)$

★━★━★━★━★━★━★━★━★━★━★━★

▂ ▄ ▅ ▆ ▇ █⚡ ᗩᖇƳᗩᑎ ⚡█ ▇ ▆ ▅ ▄ ▂

★━★━★━★━★━★━★━★━★━★━★━★

Answer 2

Answer:

Step-by-step explanation:

first term a=2

a1=2

common difference d=4

n no of terms=40

Sn=n/2( 2a+(n-1)d)

  =40/2(2.2+(40-1)4

  =20(4+39.4)

   =20(4+156)

    =20.160

     =3200