Question

 If the first term of an AP is 2 and common difference is 4, then the sum of its 40th terms is​

Answer 1

Answer:

a=2

d=4

n=40

Sn=n/2 [2a+(n-1)d}

S40=40/2[2*2+(40-1)4]

S40=20*160=3200

S40=3200

the value of its 40th term is 3200.