Question

If the first term of an AP is 2 and common
difference is 4 Find the sum of the first 40 terms​

Answer 1

Answer:

3200

Step-by-step explanation:

a=2

d =4

n=40

sum=n/2(2a+n-1)d

40/2 ( 4 + 40-1 )4

= 20×156 + 4

=160×20

= 3200

hope it helps

mark it as branliest if you want

Answer 2

3200

Step-by-step explanation:

Snth=n/2{2a+(n-1)d}

40/2{2×2+(40-1)4} = 20{4+156} = 20×160 = 3200

I hope that it is correct