If the first term of an ap is 2 and the common difference is 4 then find the sum of first 40 term
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Step-by-step explanation:
S40 = (40/2)[2*2 + (40–1)*4]
The sum of 40 terms is (it is not the sum of the 40th term)
In the AP, a = 2, d = 4 and n = 40, hence
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= 20*160
= 20[4+ 156]
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