if the first term of an ap is 3 and common difference is 5 then is 10th term is
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Here, in the question :
- First term of an AP ( a ) = 3
- Common difference ( d ) = 5
We know that :
- aₙ = a + ( n - 1 ) d
Substituting the values and finding the 10th term :
- a₁₀ = 3 + ( 10 - 1 ) ( 5 )
- a₁₀ = 3 + ( 9 ) ( 5 )
- a₁₀ = 3 + 45
- a₁₀ = 48
★ Therefore, the 10th term of the AP is 48.
Know more :
Sum of first ‘n’ terms of an AP :
- Sₙ = n / 2 [ 2a + ( n - 1 ) d ]
Sum of first ‘n’ terms of an AP :
- Sₙ = n / 2 ( a + aₙ )
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