IF the first term of an AP is 3 the sum of first 5 terms is 1/11th of the sum of next 5 terms find the 20th term
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Step-by-step explanation:
Let the first term be a
a=3
a+a+d+a+2d+a+3d+a+4d=1/11(a+5d+a+6d+a+7d+a+8d+a+9d)
=5a+10d=1/11(5a+35d)
11(5a+10d)=5a+35d
55a+110d=5a+35d
55a-5a+110d-35d=0
50a+75d=0
25(2a+3d)=0
2a+3d=0
As a=3
2(3)+3d=0
6+3d=0
3d=-6
d=-2
20th term
=a+(n-1)d
=3+(20-1)-2
=3+(19)-2
=-32
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