Question

If the first term of an ap is -5 and common difference is 2, then sum of its first the sum of terms first 6 terms *

Answer 1

given: a= -5

d= 2

To find: S6

We know that Sn=n[2a+(n-1)d]

2

S6=6[2×-5+(6-1)(2)]

2

S6=3[-10+5×2]

S6=3[-10+10]

S6=3×0

S6=0