If the first term of an AP is - 5 and the common difference is 2, then the sum of the first 6 terms is.....
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Step-by-step explanation:a = (-5)
d= (2)
S6 = n/2 {a +( a +(n-1)d)}
S6= 6/2 {(-5)+((-5)+(6-1)2}
S6= 3{ (-5)+(-5+10)}
S6= 3 {-5 -5+10}
S6= 3 × 0
S6= 0
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hope.its clear.......
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