Question

if the first term of an ap is -5 and the common difference is 2 then the sum of the 6 terms is

Answer 1

Answer:

a = -5

b = 2

$s \frac{n}{?}$

= n/-5 [ -5 a + ( n + 1 ) d ]

now,

S6,

6 /-5 [-5a + ( 6-1 ) d ]

= -1.2 [ 2 (-5) + 5(4)

= -1.2 [ -10 + 20 ]

= 1.2 [ 10]

= 1.2 [ 10]

=12