If the first term of an ap is -5 and the common difference is 2,then the sum of the first 12 terms is.............
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Solution:
Given - First term in an A. P.= -5
common difference =d= 2
To find: Sum of first 12 terms =?
Sn = n/2 [2a +(n-1)d]
S12 =12/2[ 2 ×(-5)+(12-1)2]
S12 = 6(-10 + 22)
S12 = 6+10
S12=18.
Therefore the sum of first 12 terms of A.P. is 18
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