if the first term of an ap is -5 and the common difference is 2 find the sum of first six terms.
ch 5 arithmetic progression
class 10
please answer fast
Answers
Answered by
0
Answer:
Step-by-step explanation:
Sn=n/2+[2a+(n-1)d]
n=6
a=-5
d=2
S6=6/2+[2*-5+5*2]
=3+[-10+10]
=3
Answered by
0
Answer:
63 is the sum of the first 6 numbers
Step-by-step explanation:
The formulae for finding the sum of the terms of ap is n/2 [a+l]
here n means number of terms , a means first term , l means last term d means difference
n=6
a=-5
l=26
6/2[-5+26 ]
3[21]
63
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