if the first term of an AP is -5 and the common difference is 2 than the sum of the first 6 term is
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1
Answer:
the required sum of 6 terms of the given AP is 0.
Step-by-step explanation:
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Answered by
2
Answer:
a= (-5)
d=(2)
s6= n/2{a+(a+(n-1) d}
s6=6/2{-5+(-5) +(6-1) 2}
s6= 3{-5+(-5+10)}
s6=3{-5-5+10}
s6= 3x0
s6= 0
hope it helps you Army ⟬⟭ (:
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