Question

if the first term of an ap is -5 and the common difference is 2 then the sum of the first 6 term

Answer 1

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Answer 2

t1 ( a) = -5 common difference ( d) = 2
sn = n/2[2a ( n-1) d]
S 6 = 6/2[ 2( -5) ( 6 -1) 2]
S 6 = 3 [-10( 5) 2 ]
S 6 = 3 [ -50 × 2]
S 6 = 3 × -100
= -300