if the first term of an AP is 5and d is 2 then sum of first 6 term is
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GIVEN THAT
THE FIRST TERM OF AN AP =5
THE COMMON DIFFERENCE = 2
REQUIRED FORMULA
Sn = n/2(2a+(n-1)d)
S6 = 6/2(2(5)+(6-1)2)
S6 = 3(10+10)
S6 = 3(20)
S6 = 60
SO THE SUM OF FIRST 6 TERMS IS 60
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....hope it helps....
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