If the first term of an Ap is a and its common difference is d then show that its nth term is given by {Tn = a+(n-1)d}
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let the sequence a1 a2 a3...an
now let a1=a
a2=a+d
=a+(2-1)d
a3=a2+d
=a+(3-1)d and so on
an=a+(n-1)d this formula
Now take example of a=1 and d=1 if we have to find 100 th term
a100=1+(100-1).q
a100=1+99.1
therefore a100=100
Hence proved
I hope this will help you
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