if the first term of ap is -5 & common difference is 2 then find the sum of first 6 terms
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S = n/2(2a + (n-1)d
S = 6/2[2(-5) + (6-1)(2)
S = 3(-10 + 10)
S = 3(0)
S = 0
S = 6/2[2(-5) + (6-1)(2)
S = 3(-10 + 10)
S = 3(0)
S = 0
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