If the first term of AP is 6 and common difference is 5 find 3rd term of an AP
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The second term will be 11 (=6+5), the third term will be 16 (=6+10=6+2*5). In general the nth term will be 6+(n-1)*5. Therefore the 11th term will be 6+10*5, or 56. What is the common difference of an A.P.
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a¹ + 2d = a³
6 + 2*5 = 6+10=16
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