If the first term of first Ap1 is -7 and the first term of second Ap2 is 11 and the common difference of both the Ap's is same, then the difference between their 127th terms can be:
1: 128
2: 36
3: 18
4: 4
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Sᴏʟᴜᴛɪᴏɴ :-
Let first term of AP is a1 and of second AP is a2, and common difference of both AP is d.
Than,
→ 127th term of first AP = a1 + (n - 1)d
→ T(127) = a1 + (127 - 1)d
→ T(127) = a1 + 126d
Putting given value of a1 = (-7) Now,
→ T(127) = (-7) + 126d ------- Eqn.(1) .
Similarly,
→ 127th term of second AP = a2 + (n - 1)d
→ T(127) = a2 + (127 - 1)d
→ T(127) = a2 + 126d
Putting given value of a1 = 11 Now,
→ T(127) = 11 + 126d ------- Eqn.(2) .
Now, we have to find , the difference between their 127th terms..
So ,
→ Eqn.(1) - Eqn.(2)
→ {(-7) + 126d} - {11 + 126d}
→ (-7) - 11 + 126d - 126d
→ (-18)
And,
→ Eqn.(2) - Eqn.(1)
→ {11 + 126d} - {(-7) + 126d}
→ 11 - (-7) + 126d - 126d
→ 11 + 7
→ 18.
Hence, Option (3) , 18 is correct Answer.
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