if the first term of the GP is 16 and the common ratio is 3/2 then what will be the 4th term of the GP
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Let the first term be a and the common ratio be r, then the n th term of the G.P. is given by a n=ar
n−1
. So, we have:
ar 3 =16, ar 6
=128
⇒r
3
=8⇒r=2,a=2
So, the first term and the common difference are both equal to 2.
its the answer..
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