Question

If the first three terms of an Ap are x-1, x+2, 2x+3.Then find x​

Answer 1

Given,

x+2,2x,2x+3 are in A.P.

⇒(2x)−(x+2)=(2x+3)−(2x)

2x−x−2=2x+3−2x

x−2=3

∴x=5

The consecutive numbers are : 5+2,2(5),2(5)+3

⇒7,10,13