If the first two terms of a A. P differ by 4 and eighth term is 25 , then find the Sum of first 20 terms of the A. P
saimeghana1:
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Answers
Answered by
103
Given , Second term - First term = 4
So, Common difference = d = 4 .
Given that,
Eighth term = 25
We know that Eighth term = a+7d
So , a + 7d = 25
a + 7(4) = 25 .
a = 25 - 28= -3 .
We know that,
Sum of n terms = n/2 [ 2a + (n-1)d ]
Now,
Sum of first 20 terms = 20/2 [ 2 (-3)+ (19)4 ] = 10[ -6+76 ] = 700
So, Common difference = d = 4 .
Given that,
Eighth term = 25
We know that Eighth term = a+7d
So , a + 7d = 25
a + 7(4) = 25 .
a = 25 - 28= -3 .
We know that,
Sum of n terms = n/2 [ 2a + (n-1)d ]
Now,
Sum of first 20 terms = 20/2 [ 2 (-3)+ (19)4 ] = 10[ -6+76 ] = 700
Answered by
50
Thus so
___________________________________________________________@g
SO HERE WE GO
AS IT IS GIVEN THAT THE DIFFERENCE OF THE TWO TWO TERMS OF THE A P IS 4
THEN
A + D - A = 4
. D = 4
SO
. AS 8 TH TERM IS 25
. ➡ A + 7D = 25
. A + 7 ( 4 ) = 25
. A = 25 - 28
. A = - 3
. SO
. AS
.
. S n = n / 2 { 2a + ( n - 1 ) d }
. S 20 = 20 / 2 { 2 ( - 3 ) + ( 20 - 1 ) * 4 }
. = 10 { - 6 + 76 }
. = 10 { 70 }
. = 700
. SO THE SUM OF THE 20 TERMS OF THE A P IS 700
. Hope it helps
. @g here
.
___________________________________________________________@g
SO HERE WE GO
AS IT IS GIVEN THAT THE DIFFERENCE OF THE TWO TWO TERMS OF THE A P IS 4
THEN
A + D - A = 4
. D = 4
SO
. AS 8 TH TERM IS 25
. ➡ A + 7D = 25
. A + 7 ( 4 ) = 25
. A = 25 - 28
. A = - 3
. SO
. AS
.
. S n = n / 2 { 2a + ( n - 1 ) d }
. S 20 = 20 / 2 { 2 ( - 3 ) + ( 20 - 1 ) * 4 }
. = 10 { - 6 + 76 }
. = 10 { 70 }
. = 700
. SO THE SUM OF THE 20 TERMS OF THE A P IS 700
. Hope it helps
. @g here
.
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