if the firstteam and common difference of an
arithemetic sequence are equal find the relation
between 5th term and 10th term?
Answers
Answered by
1
Answer:
Answer:
10 th term = twice of 5 th term
Step-by-step explanation:
first term a = common difference d
fifth term t5= a+(n-1)d
= a+ (5-1)d
=a+4d
=a+4a (because a =d)
=5a
tenth term t10= a+(n-1)d
=a+(10-1)d
=a+9d
=a+9a (a=d)
=10a
therefore t5 = 2* t10
Answered by
0
Step-by-step explanation:
Given that first term(a)= common difference (d)
a=d.
fifth term is a+4d= d+4d=5d.
10th term is a+9d=d+9d=10d.
relation between 5th term and 10th term is 10th term is double of 5th term.
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