If the focal distance of an end of the minor axis of an ellipse is "k" and the distance between foci is 2h, then its equation is.
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focal distance of end of mirror Axis equal to K .
=> a²e² + b² = k²
=> a²e² + a²(1-e²) = k²
=> a² = k²
=> a = k
distance between foci = 2ae = 2h
=> ae = h
So , e = h/a
=> e² = h²/a²
=> e² = h²/k²
Now, b² = a²(1-e²) = k² ( 1- h²/k²)
=> b² = k² - h²
Therefore , equation of ellipse is
=> x²/k² + y²/(k²-h²) = 1
______________________________
focal distance of end of mirror Axis equal to K .
=> a²e² + b² = k²
=> a²e² + a²(1-e²) = k²
=> a² = k²
=> a = k
distance between foci = 2ae = 2h
=> ae = h
So , e = h/a
=> e² = h²/a²
=> e² = h²/k²
Now, b² = a²(1-e²) = k² ( 1- h²/k²)
=> b² = k² - h²
Therefore , equation of ellipse is
=> x²/k² + y²/(k²-h²) = 1
______________________________
Answered by
4
Answer:
Step-by-step explanation:
focal distance of end of mirror Axis equal to K .
=> a²e² + b² = k²
=> a²e² + a²(1-e²) = k²
=> a² = k²
=> a = k
distance between foci = 2ae = 2h
=> ae = h
So , e = h/a
=> e² = h²/a²
=> e² = h²/k²
Now, b² = a²(1-e²) = k² ( 1- h²/k²)
=> b² = k² - h²
Therefore , equation of ellipse is
=> x²/k² + y²/(k²-h²) = 1
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