Question

If the focal distance of the end of minor axis of an ellipse is q & distance between its foci is 2p,
then find its equation.

Answer 1

Explanation:

If the focal distance of an end of the minor axis of an ellipse (referred to its axes as the axes of xandy , respectively) is k and the distance between its foci is 2h, them find its equation.

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Answer 2

Answer:

If the focal distance of an end of the minor axis of an ellipse (referred to its axes as the axes of xandy , respectively) is k and the distance between its foci is 2h, them find its equation.

(or)

Distance between foci=2h

Then, 2ae=2h

             ae=h

      

        and b=k

              b2=k2

We know that,  b2=a2(1−e2)

                          b2=a2−a2e2

Substituting the values, we get

  k2=a2−h2              

         

  a2=k2+h2

Hence equation of ellipse a2x2+b2y2=1

                                             k2+h2x2+b2y2=1

                                                          OR

                                             k2x2+k2+