if the focal length of a lens is 5 CM then what is the power of the lens
Answers
Answer:
Divide the diagonal measure of the sensor/film into the focal length. On a modern “full-frame” sensor a 50mm lens would be approximately 1.1–1.3x (“full-frame” is not the same from brand to brand, since different companies buy their sensors from varous sources)(that’s right, neither the big-N nor the big-C make their own sensors). The same 50mm lens on a smaller APSC sensor becomes 1.4–1.6x. Keep in mind, this only holds true for normally designed “rectilinear” lenses, and does not necessarily apply to “fish-eye,” rare annular lenses, etc. Also, very important to understand when adapting lenses from one company to another brand/format camera, two lenses of identical focal length, i.e., “50mm,” while of identical magnification on a given sensor/film format, if one is designed for a smaller sensor/film format it probably will not project an image circle large enough to cover the larger sensor/film format. In plain language, lenses designed for larger sensors/film formats will adapt nicely to smaller sensors/film formats (with a corrsponding increase in magnification), but if you reverse the process you’ll get varying degrees of “vignetting” (darkening) in the corners of the image, or at the edges and corners of the frame there will be no image at all.
In summary, the “magnification” of any standard camera lens can be determined by dividing the diagonal measurement of the sensor/film into the focal length of the lens. =20
Answer with explanation:
f = 5 cm
= 0.05 m
P= 1/f
P= 1/0.05
P= 20 D
As the power is positive, it is converging lens.