Question

If the focal length of a magnifier is 5 cm. Calculate the magnifying power of the lens for relaxed and
strained eye.
o 6.5
0 5,6
10. 12
O 12, 10​

Answer 1

Answer:

The magnifying power of a simple microscope depends on the ratio Df for a ... -1uo=14-120 ⇒-1u0=5-120=420⇒ u0=204=5 cm ... Magnification for a normal relaxed eye, m = 5

Answer 2

Given : The focal length of magnifier is 5cm.

To find : magnifying power of the lens for relaxed and strained eyes.

solution : magnifying power of lens for relaxed eyes = $\frac{D}{f_e}$

here D = 25 cm , $f_e$ = 5 cm

then, magnifying power of lens for relaxed eyes = $\frac{25cm}{5cm}=5$

again, magnifying power of lens for strained eyes = $\left(1+\frac{D}{f_e}\right)$

= $\left(1+\frac{25cm}{5cm}\right)=6$

Therefore magnifying power of lens for relaxed and strained eyes are 5 and 6 respectively.

hence option (B) 5, 6 , is correct choice.

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